"\\Delta"H = Q/"\\nu" = c * m(H2O) * "\\Delta"T / (m / M) = c * m(H2O) * M * "\\Delta"T / m =
= 4.2 J / (g * oC) * 100 g * (25 - 23) oC * 143.3 g/mol / 2.15g = 55987 J/mol = 55.987 kJ/mol (approximately 56kJ/mol)
Answer: the heat of the reaction is 56kJ/mol
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