Answer to Question #115529 in General Chemistry for Cam

General Chemistry

Question #115529

what volume of 0.676 mol/l sulfuric acid can be neutralized 27 mL of 0.385 moles/liters barium hydroxide

Expert's answer

Ba(OH)2 + SO3 = BaSO4 + H2O.

27 x 0.385 / 1000 = 0,010395.

0,010395/0.676= 0,0153772189.

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