Solution.
1.
"m(NaCl)=5.85g;"
"V(H_2O)=100L;"
"M(NaCl)=58g\/mol;"
"Molarity=\\dfrac{mol solute}{L solution};"
"\\nu(NaCl)=\\dfrac{m(NaCl)}{M(NaCl)};"
"\\nu(NaCl)=\\dfrac{5.85g}{58g\/mol}=0.1mol;"
"Molarity=\\dfrac{0.1}{100}=0.0001mol\/L;"
2.Agitation and larger surface area;
Answer: 1. "Molarity=0.0001mol\/L;"
2.Agitation and larger surface area.
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