First we will calculate heat change due to 0.75 g of CaO and then we will convert it accordingly for 1 mole of CaO
heat generated = mcΔ\DeltaΔT=100×4.184×6.15+51.6×0.138×6.15=2617joules100\times4.184\times6.15+51.6\times0.138\times6.15=2617 joules100×4.184×6.15+51.6×0.138×6.15=2617joules
molar mass of CaO =56
ΔH=560.75×2617=195400J\Delta H=\frac{56}{0.75}\times2617=195400JΔH=0.7556×2617=195400J
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