Answer to Question #113826 in General Chemistry for fahad

Question

a) oil flows in a pipe of diameter 75 mm diameters at at a rate of 100 imperial gallons per minute . if the density of the oil is 0.86 g/cc , find the mass flow rate of the oil in kg/hr

b) what is the equivalent mole of Na2SO4 in 100g of Na2SO4.10H2O crystals

Answer 1

A) 1 imp. gallon = 4.546 liters

100 gallons = 454.6 liters

m(oil) = 454600cc*0.86g/cc = 390956 g/minute

m(oil) = 390.956kg*60minute = 23457.4 kg/hr

B) We need the g formula weight of the anhydrous salt and the decahydrate.

Na2SO4 = 142

Na2SO4. 10H2O = 322

so 100g of Na2SO4=100x322/142g decahydrate, ie 226g

of this 100g has crystallised out leaving 126g in solution