Answer to Question #113820 in General Chemistry for joemar

Question

how many moles are there in 2.48x10^(25)potassium atom of KNO_(3)

Answer 1

Solution.

One mole contains $6.02\sdot10^{23}$ atoms(Avogadro number);

The $\nu$ moles are contained $2.48\sdot10^{25}$ atoms;

From proportion we find $\nu$ : $\nu=\dfrac{1mol\sdot2.48\sdot10^{25}}{6.02\sdot10^{23}}=41.196mol;$

Answer: $\nu = 41.196mol.$