Answer to Question #113618 in General Chemistry for Paulette Matthews

Question

At standard temperature and pressure (0 ∘C and 1.00 atm ), 1.00 mol of an ideal gas occupies a volume of 22.4 L. What volume would the same amount of gas occupy at the same pressure and 95 ∘C ?

Answer 1

P₁ = P₂ = 1.00 atm = constant;

V₁ = 22.4 L;

T₁ = 0 °C = 273.15 K;

T₂ = 95 °C = 368.15 K;

V₂ = unknown;

Solution:

(P₁×V₁)/(T₁) = (P₂×V₂)/(T₂);

P₁ = P₂ = constant;

(V₁)/(T₁) = (V₂)/(T₂);

V₂ = (V₁×T₂)/(T₁);

V₂ = (22.4 L × 368.15 K)/(273.15 K) = 30.19 L;

Answer: 30.19 L