Answer to Question #113586 in General Chemistry for Emma

Question #113586
calculate the final pH when 120.0mL of 0.50M HI is added to 850 mL of 0.05M HClO4
1
Expert's answer
2020-05-03T15:22:58-0400

Solution.

V(HI)=120.0mL=0.120L;V(HI) = 120.0mL=0.120L;

M(HI)=0.50M;M(HI) =0.50M;

V(HClO4)=850mL=0.850L;V(HClO_4) =850mL=0.850L;

M(HClO4)=0.05M;M(HClO_4)=0.05M;

ν(HI)=V(HI)M(HI);ν(HI)=0.120L0.50M=0.06mol;\nu(HI)=V(HI)\sdot M(HI); \nu(HI)=0.120L\sdot0.50M=0.06mol;

ν(HClO4)=V(HClO4)M(HClO4);\nu(HClO_4)=V(HClO_4)\sdot M(HClO_4);

ν(HClO4)=0.850L0.05M=0.0425mol;\nu(HClO_4)=0.850L\sdot0.05M=0.0425mol;

νfinal=0.06mol+0.0425mol=0.1025mol;\nu_{final}=0.06mol+0.0425mol=0.1025mol;

[H3O+]=νfinalVfinal;[H3O+]=0.1025mol0.970L=0.1057M;[H_3O^+]=\dfrac{\nu_{final}}{V_{final}}; [H_3O^+]=\dfrac{0.1025mol}{0.970L}=0.1057M;

pH=lg[H3O+]=lg(0.1057)=lg9.46=0.976pH=-lg[H_3O^+]=-lg(0.1057)=lg9.46=0.976 ;

Answer: pH=0.976.pH=0.976.



Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment