Solution.
V(HI)=120.0mL=0.120L;
M(HI)=0.50M;
V(HClO4)=850mL=0.850L;
M(HClO4)=0.05M;
ν(HI)=V(HI)⋅M(HI);ν(HI)=0.120L⋅0.50M=0.06mol;
ν(HClO4)=V(HClO4)⋅M(HClO4);
ν(HClO4)=0.850L⋅0.05M=0.0425mol;
νfinal=0.06mol+0.0425mol=0.1025mol;
[H3O+]=Vfinalνfinal;[H3O+]=0.970L0.1025mol=0.1057M;
pH=−lg[H3O+]=−lg(0.1057)=lg9.46=0.976 ;
Answer: pH=0.976.
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