Answer to Question #113605 in General Chemistry for Nicolas

Question

Calculate the pH of a 0.0237 M solution of KOH.

Answer 1

KOH is a strong base and will dissociate completely in water. For every mole of KOH, there will be 1 mole of OH^-, so the concentration of OH^- will be the same as the concentration of KOH.

[OH^-] = 0.0237 M;

pOH + pH = 14;

pOH = −log([OH^-]);

pOH = −log(0.0237);

pOH = 1.62;

pH = 14 − 1.62;

Answer: pH = 12.38