Answer to Question #112820 in General Chemistry for Jonathan Jacques Pluviose

Question

9.) If there are 0.045 mols of NH3 in 23.6 mL of solution, what is its concentration? Also,
what is the pH?


10.) If there are 0.0345 mols of HI in 47 mL of solution, what is its concentration? Also, what
is the pH?

Answer 1

9) C(NH₃) = 0.045 mol/ 0.0236 L = 1.906 M

pН = 14 – ½рК_В + ½lgС

pH = 14 - 2.37 + 0.14 = 11.77

10) C(HI) = 0.0345 mol/ 0.047 L = 0.73 M

pH = - lg[HI] = 0.14