Answer to Question #112814 in General Chemistry for Jonathan Jacques Pluviose

Question

Calculate the OH-1 concentration in 0.0325 M HCl.

Answer 1

Solution.

$pH+pOH =14;$

$pH = -lg[H_3O^{+}];$

$pOH = -[OH^{-}];$

$pH = -lg[0.0325] = 1.49;$

$1.49+pOH = 14;$

$pOH = 12.51;$

$pOH = -lg[OH^{-}];$

$10^{-POH}$ = $[OH^{-}];$

$10^{-12.51} =$ $[OH^{-}];$

$[OH^{-}] = 3.09\sdot10^{-13}$ $mol/L;$

Answer: $[OH^{-}] = 3.09\sdot10^{-13};$