Solution.
pH+pOH=14;pH+pOH =14;pH+pOH=14;
pH=−lg[H3O+];pH = -lg[H_3O^{+}];pH=−lg[H3O+];
pOH=−[OH−];pOH = -[OH^{-}];pOH=−[OH−];
pH=−lg[0.0325]=1.49;pH = -lg[0.0325] = 1.49;pH=−lg[0.0325]=1.49;
1.49+pOH=14;1.49+pOH = 14;1.49+pOH=14;
pOH=12.51;pOH = 12.51;pOH=12.51;
pOH=−lg[OH−];pOH = -lg[OH^{-}];pOH=−lg[OH−];
10−POH10^{-POH}10−POH = [OH−];[OH^{-}];[OH−];
10−12.51=10^{-12.51} =10−12.51= [OH−];[OH^{-}];[OH−];
[OH−]=3.09⋅10−13[OH^{-}] = 3.09\sdot10^{-13}[OH−]=3.09⋅10−13 mol/L;mol/L;mol/L;
Answer: [OH−]=3.09⋅10−13;[OH^{-}] = 3.09\sdot10^{-13};[OH−]=3.09⋅10−13;
