Question

5.) Calculate the pH of a 2 M solution of H2SO4.



6.) If a 65 mL solution of HCl has a concentration of 0.326 M, what is its pH? Also, how many

grams of HCl are in the solution?

Answer 1

H2SO4 is strong electrolyte, completely dissolves into ions:

H2SO4 <=> 2H⁺ + SO4^-

Hence: [H+]=4mol/l

pH=-lg [H+]=-lg4=-0,6 (negative meaning pH)

HCl is strong electrolyte, completely dissolves into ions:

HCl <=> H⁺+Cl^-

Hence: [H+]=0,326mol/l

pH=-lg [H+]=-lg0,326=0,49

c(HCl)=0,326mol/l

Hence in 65ml located: n= (0,065L*0,326mol)/1L=0,021mol

m(HCl)= 0,021mol*36,5g/mol=0,77g