Answer to Question #112815 in General Chemistry for Jonathan Jacques Pluviose

Question

Calculate the H3O+1 concentration in 0.00500 M NaOH.

Answer 1

Kw = 1*10^-14 = [H₃O⁺][OH^-]

The amount of dissociated water is relatively small, so we count C(OH^-) that was only formed by dissociation of NaOH.

[OH^-] = 0.005 M

[H₃O⁺] = Kw/[OH^-] = 1*10^-14/0.005 = 2*10^-12