Question

A sample that contains 3.98 mol of a gas at
255 K has a pressure of 0.621 atm. What is
the volume?

Answer 1

$P=0.621\ atm,V=?,T=255K,n=3.98$

Using ideal gas equation,$PV=nRT$ and $R=0.0821\ L\ atm\ mol^{-1}K^{-1}$

On substituting these values,

$0.621\times V=0.0821\times 3.98\times 255\implies V=134\ L$