m (Fe) = 3.01 g
n(Fe) = m / M = 3.01 g / 55.845 g/mol = 0.054 mol
P(CO) = 732 mm Hg / 760 mm Hg = 0.963 atm
T(CO) = 23°C = 23 + 273.15 = 296.15 K
V(CO) = 5.36 L
P x V = n x R x T
n = P x V / R x T = 0.963 atm x 5.36 L / 0.082057 L•atm/(K•mol) x 296.15 K = 0.212 mol
Fe(s) + 5CO(g) ---> Fe(CO)5(l)
Fe is excess reactant and CO is limiting rectant
n(Fe(CO)5) = n(CO) / 5 = 0.212 / 5 = 0.0424 mol
m(Fe(CO)5) = n(Fe(CO)5) x M(Fe(CO)5) = 0.0424 mol x 196 g/mol = 8.31 g
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