Question

What volume of NO gas will be produced from 4.00 moles of N₂ and 3.00 moles of O₂ at STP according to the following equation? N₂(g)+ O₂(g) → 2NO(g)

Answer 1

As per the reaction $N_2(g)+ O_2(g) → 2NO(g)$ ,

Moles of $N_2$ reacted $=$ Moles of $O_2$ reacted.

And,$4$ moles of $N_2$ and $3$ moles of $O_2$ are given,So oxygen will be limiting reagent.So,amount of oxygen will decide the moles of $NO$ formed.

And, Moles of $NO$ formed$=2\times$Moles of $O_2$ reacted=2\times3=6\moles.