Answer to Question #111235 in General Chemistry for Jonathan

Question

A 350 mL solution has an osmotic pressure of 2.73 x 10^-3 atm. If 0.21g of solute was added to the solution, what is the molar mass of the solute?

Answer 1

Law of VantGoff $\pi=C_m*R*T=((m/M)/V)*R*T$

$M=(m*R*T)/(\pi*V)$

$M=0.21g*R*273,15K*0.35l=(0.21g*0.082*273*0.35)/mol$

M=602,7g/mol