Answer to Question #111158 in General Chemistry for Bianca

Question

If the diffusion coefficient of oxygen in the vitreous humour in the eye is 4.2×10−7 m2 s−1 how long does it take oxygen to diffuse an average distance of 1.0 mm through the vitreous humour? (to 2 s.f and in s)

Answer 1

D=4.2×10^-7 m2 s^-1

d=1mm

mass m of oxygen=32g

$\delta m=\frac {D*\delta t}{d}$

dt=(32*1)/4.2×10^-7

dt=7.6*10⁷