2LiOH(s) + CO2(g) --> Li2CO3(s) + H2O(l)
There is 3.0 L of CO2 gas at a pressure of 1.5 atm and a temperature of 300 K. What mass of LiOH would be used to react with this amount of CO2?
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Expert's answer
2020-04-22T09:17:36-0400
pV= nRT.
n= pV/RT = 1.5 x 3 / 0.082 x 300 = 0.182926829 moles of CO2
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