Answer to Question #245094 in Molecular Physics | Thermodynamics for Kelani

Question #245094

A spaceship's orbital maneuver requires a speed increase of 1.35  103 m/s. If its engine has an exhaust speed of 2.25  103 m/s, determine the required ratio Mi/Mf

 of its initial mass to its final mass. (The difference Mi − Mf

 equals the mass of the ejected fuel.)



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1
Expert's answer
2021-10-04T14:35:25-0400

According to Raw q conservation q momentum we have:

"(M+\u0394m)V = M(v+\u0394v)+\u0394m(v-v_e) \\\\\n\nm\u0394v=v_e\u0394m \\\\\n\n\u0394m=-\u0394M \\\\\n\nM\u0394v =-v_e\u0394M \\\\\n\nv_f-v_i =v_eln(\\frac{M_i}{M_f}) \\\\\n\n\\frac{v_f-v_i}{v_e} = ln(\\frac{M_i}{M_f}) \\\\\n\n\\frac{1.35 \\times 10^3}{2.25 \\times 10^3} = ln(\\frac{M_i}{M_f}) \\\\\n\n\\frac{M_i}{M_f} = e^{\\frac{1.35}{2.25}} = e^{0.6}=1.822"


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