Question #175905

An integrable function can have finitely many points of discontinuous.

True or false with full explanation


Expert's answer

Let [a,a1],[a2,a3],...,[an,b][a,a_1], [a_2,a_3], ..., [a_n,b] are the intervals of continuity of the function and

a1,a2,...,ana_1, a_2, ..., a_n points of discontinuities. We know that continuous functions are integrable and the integral is additive, so the following formula holds:

∫abf=∫aa1f+∫a1a2f+...+∫anbf\int_a^bf=\int_a^{a_1}f+\int_{a_1}^{a_2}f+...+\int_{a_n}^bf

If f is an integrable function, then all integrals exist, so the statement is true



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