An integrable function can have finitely many points of discontinuous.
True or false with full explanation
Let "[a,a_1], [a_2,a_3], ..., [a_n,b]" are the intervals of continuity of the function and
"a_1, a_2, ..., a_n" points of discontinuities. We know that continuous functions are integrable and the integral is additive, so the following formula holds:
"\\int_a^bf=\\int_a^{a_1}f+\\int_{a_1}^{a_2}f+...+\\int_{a_n}^bf"
If f is an integrable function, then all integrals exist, so the statement is true
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