Question #271014

xdy/dx + (x+1) y = x³

Expert's answer

xdydx+(x+1)y=x3x\frac{dy}{dx}+(x+1)y=x^3

dydx+(x+1)xy=x2\frac{dy}{dx}+\frac{(x+1)}{x}y=x^2

This is a linear differential equation of the first order

I.F=e∫x+1xdx=e∫1x+1dx=eln x+xI.F=e^{\int \frac{x+1}{x}}dx=e^{\int \frac{1}{x}+1dx}=e^{ln\ x+x}

Solution to the equation;

y⋅(I.F)=∫x2(I.F)dx+Cy\cdot (I.F)=\int x^2(I.F)dx+C

yeln x+x=∫x2(eln x+x)dx+Cye^{ln\ x+x}=\int x^2(e^{ln\ x+x})dx+C

y⋅eln x+x=∫x2⋅eln x⋅exdx+C=∫x3⋅exdx+Cy\cdot e^{ln\ x+x}=\int x^2\cdot e^{ln\ x}\cdot e^{x}dx+C=\int x^3\cdot e^{x}dx+C

y⋅(x⋅ex)=[(x3)(ex)−(3x2)(ex)+(6x)(ex)−(6)(ex)]+Cy\cdot(x\cdot e^x)=[(x^3)(e^x)-(3x^2)(e^x)+(6x)(e^x)-(6)(e^x)]+C

y⋅(x)=x3−3x2+6x−6+Ce−xy\cdot(x)=x^3-3x^2+6x-6+Ce^{-x}

y=x2−3x+6−6x+Cxe−xy=x^2-3x+6-\frac{6}{x}+\frac{C}{x}e^{-x}



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