Find the linear substitution that reduces the inhomogeneous equation to the homogeneous one: y,=x+y-3/y-x+1
A first order differential equation
"dy\/dx=f(x,y)"
is called homogeneous equation, if the right side satisfies the condition
"f(tx,ty)=f(x,y)"
we have:
"f(x,y)=x+\\frac{y-3}{y-x}+1"
then:
"f(tx,ty)=tx+\\frac{ty-3}{ty-tx}+1"
"x+\\frac{y-3}{y-x}+1=tx+\\frac{ty-3}{ty-tx}+1"
"x(y-x)+y-3=t^2x(y-x)+ty-3"
"x(y-x)(t^2-1)+y(t-1)=0"
"x(y-x)(t+1)+y=0"
"t=-\\frac{y}{x(y-x)}-1"
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