1.- The equilibrium price can be found when S(p)=100+p+pt and D(p)=200-p-pt are both equal to the same value and then:
S(p)=D(p)100+p+pt=200−p−pt⟹p+pt=50
Then, if we consider the last we find that:
⟹p+pt=50100+(p+pt)=200−(p+pt)100+50=200−50S(p)=D(p)=150
2.- We find first the average of the supply to then differentiate it and find the price:
S=S(p)/p=p100+1+pt−1=1+p100+pt
dpdS=p2pt(t−1)−100=0
⟹pt=(t−1)100⟹p=[(t−1)100]1/t
The only condition that has to be satisfied as well is that t>1.
3.- If we make the graphs by using the value of p(0) we find
- With p(0)=75 the supply is higher than the demand after several times.
- On the other hand, if we analyze p(0)=25 the supply converges with the demand in the first year and then its behavior is like in the prior example.
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