I am having two types of files. type1 : 2009.htm, 2010.htm, 2011.htm, 2012.htm
type2: file1.txt, file2.txt, file3.txt, file4.txt
now I have to process the .htm file and write the processed data into the .txt file.
the code for the processing is :
f = open('2009.htm', 'r+')
text = f.read()
pattern = ""
for match in re.findall(pattern, text):
if True:
html = text.replace("", "
")
f1 = open('file1.txt', 'r+')
f1.write(html)
f1.close()
now I have to automate this for all the files using for loops. i have tried one code but in that only the first file is getting copied into all the files.
list1 = ['2009.htm', '2010.htm', '2011.htm', '2012.htm',
for x in list1:
for y in list2:
f = open(x, 'r+')
text = f.read()
pattern = ""
for match in re.findall(pattern, text):
if True:
html = text.replace("", "
")
f1 = open(y, 'r+')
f1.write(html)
f1.close()
now what I have do?
1
Expert's answer
2014-03-05T12:38:26-0500
We propose the following way:
import re;
list1 = ['D:\2009.htm', 'D:\2010.htm'] list2 = ['D:\file1.txt', 'D:\file2.txt'] for x in zip(list1, list2): f = open(x[0], 'r+') text = f.read() pattern = "aaa" for match in re.findall(pattern, text): if True: html = text.replace("aaa", "bbb") f1 = open(x[1], 'w+') f1.write(html) f1.close() f.close();
Here zip function allows to obtain input file name as x[0] (because list1 is the first argument), and the output file name as x[1] (because list2 is the second argument in zip), see https://docs.python.org/2/library/functions.html#zip for details.
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