Answer to Question #283735 in Python for Venu

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Question #283735

Most frequentl digit in python

Expert's answer

s = input()
ans = [0, 0]
ss =set(s)


for i in ss:
    if ans[0] < s.count(i):
        ans[0] = s.count(i)
        ans[1] = i

print(ans[1])

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