Answer to Question #283593 in Python for Evans Mulenga

Question

Start with the following Python code.

alphabet = "abcdefghijklmnopqrstuvwxyz"

test_dups = ["zzz","dog","bookkeeper","subdermatoglyphic","subdermatoglyphics"]

test_miss = ["zzz","subdermatoglyphic","the quick brown fox jumps over the lazy dog"]

def histogram(s):

d = dict()

for c in s:

if c not in d:

d[c] = 1

else:

d[c] += 1

return d

The function has_duplicates should take a string parameter and return True if the string has repeated characters. Otherwise, it should return False.

Use has_duplicates by creating a histogram using the histogram function above.

Write a loop over the strings in test_dups list.

write a function missing_letters that takes a string parameter and returns a new string with all the letters of the alphabet that aren't in the argument string. The letters in the returned string should be in alphabetical order

Answer 1

alphabet = "abcdefghijklmnopqrstuvwxyz"
test_dups = ["zzz","dog","bookkeeper","subdermatoglyphic","subdermatoglyphics"]
test_miss = ["zzz","subdermatoglyphic","the quick brown fox jumps over the lazy dog"]


def histogram(s):
    d = dict()
    for c in s:
        if c not in d:
            d[c] = 1
        else:
            d[c] += 1
    return d


def has_duplicates(s):
    for v in histogram(s).values():
        if v > 1:
            return True
    return False


def test_dups_loop():
    for s in test_dups:
        print(s + ':', has_duplicates(s))


def missing_letters(s):
    r = list('abcdefghijklmnopqrstuvwxyz')
    s = s.lower()
    for c in s.lower():
        if c in r:
            r.remove(c)  
    return ''.join(r)


def test_miss_loop():
    for s in test_miss:
        print(s + ':', missing_letters(s))


def main():
    test_dups_loop()
    test_miss_loop()


if __name__ == '__main__':
    main()