Answer to Question #266029 in Python for Sam

Question

You can approximate n by using the following summation:

n=4(1 - 1/3 + 1/5 - 1/7 + 1/9 - 1/11 + ..... + (-1)i + 1/2i - 1

Write a program that displays the n value for i = 10000, 20000, … and 100000.

Program Output:

3.1414926535900345

3.1415426535898248

3.141559320256462

3.1415676535897985

3.1415726535897814

3.141575986923102

3.141578367875482

3.1415801535897496

3.1415815424786238

3.1415826535897198

Answer 1

#function for finding the approximate number

def pi_approx(n):

#adding number to n variable  

   

  return 4*sum([((-1)**i)/(2*i+1) for i in range(10000)])