Answer to Question #209668 in Python for sudheer

Question

Given a matrix of order M*N and a value K, write a program to rotate each ring of the matrix clockwise by K elements. If in any ring has less than or equal to K elements, then don’t rotate that ring.Input

For example, if the given M and N are 4 and 4 respectively. If the matrix elements are

1 2 3 4

5 6 7 8

9 10 11 12

13 14 15 16

If the given K is 3. Rotate each ring of the matrix by 3 elements.

In the above matrix, the elements (1, 2, 3, 4, 8, 12, 16, 15, 14, 13, 9, 5) is a ring, similarly, the elements (6, 7, 11, 10) will make a ring.

Therefore, by rotating each ring in clockwise direction by 3 elements will give (13, 9, 5, 1, 2, 3, 4, 8, 12, 16, 15, 14) and (10, 6, 7, 11). So the output should be

13 9 5 1

14 7 11 2

15 6 10 3

16 12 8 4

Answer 1

M, N = input().split(' ')
M, N = int(M), int(N)
matrix = []
for _ in range(M):
	row = [int(x) for x in input().split(' ')]
	matrix.append(row)

K = int(input())

values = matrix[0][:-1] + [x[-1] for x in matrix][:-1] + matrix[-1][::-1][:-1] + [x[0] for x in matrix][::-1][:-1]

values = values[-K:] + values[:-K]
print(values)

output = matrix

idxs = [(0, j) for j in range(N)][:-1] + [(i, N - 1) for i in range(M)][:-1] + [(M - 1, j) for j in range(N)][::-1][:-1] + [(i, 0) for i in range(M)][::-1][:-1]

idx = 0
for i, j in idxs:
	output[i][j] = values[idx]
	idx += 1

print(output)