Answer to Question #243538 in Java | JSP | JSF for ehtisham

Question

write a functoin that given a three digit integer n and an integer 

k return the maximum possible three digit value that can be obtained 

by performing at most k increase by 1 of any digit in n 

Answer 1

package maximumpossiblevalue;




public class MaximumPossibleValue {
   public static int maximum(int num, int k){
       String string = String.valueOf(num);
       char first_character = string.charAt(0);
       String a = String.valueOf(first_character);
      int first = Integer.parseInt(a);
      
      
       char second_character = string.charAt(1);
       String b = String.valueOf(second_character);
      int second = Integer.parseInt(b);
      
      
       char third_character = string.charAt(2);
       String c = String.valueOf(third_character);
      int third = Integer.parseInt(c);
      
       int first_temp = first;
       for(int i=1; i<=k; i++){
           first_temp++;
       }
       String first_max = String.valueOf(first_temp) + String.valueOf(second) + String.valueOf(third);
        
        int second_temp = second;
        for(int i=1; i<=k; i++){
           second_temp++;
       }
        String second_max = String.valueOf(first) + String.valueOf(second_temp) + String.valueOf(third);
        
        int third_temp = third;
       for(int i=1; i<=k; i++){
           third_temp++;
       }
       
        String third_max = String.valueOf(first) + String.valueOf(second) + String.valueOf(third_temp);
       
        int first_possible= Integer.parseInt(first_max);
        int second_possible= Integer.parseInt(second_max);
        int third_possible= Integer.parseInt(third_max);
        int [] arr= {first_possible,second_possible, third_possible};
        int max = arr[0];
        for(int i=0; i<3; i++){
            if(arr[i]>max){
                max = arr[0];
            }
        }
        return max;
   }
    public static void main(String[] args) {
       System.out.printf("\nMaximum possible three digit value %d\n",  maximum(476,5));
       
    }
    
}