In a digital transmission, the sender clock is 0.2 percent faster than the receiver clock.
How many extra bits per second does the sender send if the data rate is I Mbps?
The sender clock is 0.2 persent fasterthat means data is sent for an extra time of 0.002 sec. Number of bits sent = Time period * bandwidth.
Given that bandwidth of the channel is 1 Mbps = "10^6" bps.
The number of bits sent from source to destination for the time period 0.002 sec is "0.002 * 10^6 =2000" bits.
Therefore 2000 extra bits are sent from the source.
Comments
Leave a comment