Question

In a digital transmission, the sender clock is 0.2 percent faster than the receiver clock.

How many extra bits per second does the sender send if the data rate is I Mbps?

Answer 1

The sender clock is 0.2 persent fasterthat means data is sent for an extra time of 0.002 sec. Number of bits sent = Time period * bandwidth.

Given that bandwidth of the channel is 1 Mbps = $10^6$ bps.

The number of bits sent from source to destination for the time period 0.002 sec is $0.002 * 10^6 =2000$ bits.

Therefore 2000 extra bits are sent from the source.