Answer to Question #47982 in C++ for Sam

Question

My instructor gave us an assignment composed of 4 problems. I was able to do 3 out of 4. I still have one but I have no idea how to write the program. The question is:

Write a program to allow the user to enter a number between 10 and 80 inclusive. You have to keep asking the user to enter a number in that range if he doesn’t (use do-while). Then call a function that will list all the combinations of two integers (other than 1*the number itself) that their multiplication is equal to the entered number. Example; if the user entered 36 then your output will be: <2, 18> <3, 12> <4, 9> <6, 6>.

Please help?

Answer 1

#include <cmath>
#include <iostream>
using namespace std;
void print_multiplications(int n) {
bool first = true;
for (int i = 2; i <= sqrt(n); ++i) {
if (n % i == 0) {
if (!first) cout << ", ";
cout << "<" << i << ", " << n / i << ">";
first = false;
}
}
cout << endl;
}
int main() {
int n = 0;
do {
cout << "Input a number between 10 and 80: ";
cin >> n;
} while (n < 10 || n > 80);
print_multiplications(n);
}