1+1/2+1/3+...+1/n
Write a program that compares the results of the
summation of the preceding series, computing from left to
right and from right to left with n = 50000
1
Expert's answer
2015-06-04T03:31:25-0400
#include <iostream> #include <cstdio> int main() { int n = 50000; double sum1 = 0; double sum2 = 0; for (int i = 1; i <= n; i++) { sum1 += 1 / (double) i; } for (int i = n; i >= 1; i--) { sum2 += 1 / (double) i; } printf("Sum from left to right: %f\n", sum1); printf("Sum from right to left: %f", sum2); }
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