Answer to Question #312130 in C++ for Ali

Question

Write a program which takes a number n as input and prints YAYY if the sum of all digits except the rightmost digit is equal to the rightmost digit., otherwise print OOPS. For example: If user enters 2237, it will print YAYY because 2+2+3 is equal to 7. Whereas, if user enters 3425, it will print OOPS because 3+4+2 is not equal to 5. 

you can only use conditional structures . NO loops.

Answer 1

#include <iostream>

using namespace std;

int SummAcc(int num)
{
	static int summ = 0;
	if (num > 0)
	{
		summ += num % 10;
		SummAcc(num / 10);
	}
	return summ;
}

int main()
{
	int n;
	cout << "Please, enter a number n: ";
	cin >> n;
	int last = n%10;
	int res = SummAcc(n/10);
	if (res == last)
		cout << "YAYY";
	else
		cout << "OOPS";
}