Answer to Question #290628 in C++ for Yaku

Question

The function has the following functionality:

exp(x, y) =

| 0, x = 0,

| 1, \forall x \notequal 0 and y = 0.

| x^y, otherwise

As a result of the above, write a corresponding recursive C++ function, exp(x, y), computing the exponentiation function with the given specifications.

Answer 1

#include <iostream>
using namespace std;

double exp(double x, int y) {
    if (y < 0) {
        return exp(x, -y);
    }
    if (x == 0) {
        return 0;
    }
    if (y == 0) {
        return 1.0;
    }
    return exp(x, y-1) * x;
}

int main() {
    double x;
    int y;

    cout << "Enter x: ";
    cin >> x;
    cout << "Enter y: ";
    cin >> y;
    cout << "exp(" << x << ", " << y << ") =  " << exp(x, y);


    return 0;
}