Answer to Question #290473 in C++ for mark

Question

Search and Rescue

by CodeChum Admin

Make a program that will accept an integer and loop for the same number of times as that of the inputted integer and input random integers and add it to the array/list one by one, per line. Afterwards, make your program accept another random integer.

Using that final integer, compare from your array/list if the final integer's value is also present in your current array/list. If so, print "Present"; otherwise, print "None".

Start coding now!

Input

The first line contains the size of the array.

The next lines contain the integers.

The last line contains an integer to be searched.

5
3
21
2
5
23
2

Output

A line containing a string.

Present

Answer 1

#include <iostream>
#include <string>




using namespace std;






int main(void){
	int size;
	cin>>size;
	int* numbers = new int[size];
	for (int i = 0; i < size; i++) {
		cin>>numbers[i];
	}
	int x;
	cin>>x;


	bool isFound = false;
	for (int i = 0; i < size; i++) {
		if (numbers[i] == x) {
			isFound = true;
		}
	}
	if (isFound == true) {
		cout<<"Present\n";
	} else {
		cout<<"None\n";
	}




	system("pause");
	return 0;
}