Answer to Question #271324 in C++ for Sarang

Question

Create a user-defined function that will accept a 3 x 3 matrix (2D Array), set it as a parameter. Say mad [3][3]; feel free to use your initials.

Function name should InitialsMatrix (ie. MadMatrix)

The function should store 9 values to the array; it only accept values 0 and 1.

It should be outputted in a table format

0 1 1

1 1 1

1 0 0

Display the sum of values if it is an even value

Use a double for loop to implement this

Screen Layout

Input 0's and 1's to the mad [3][3] matrix

mad[0][0]:0

mad[0][1]:1

mad[0][1]:1

mad[0][1]:1

mad[0][1]:1

mad[0][1]:1

mad[0][1]:1

mad[0][1]:0

mad[0][1]:0

Output Table Format

0 1 1

1 1 1

1 0 1

Sum is 6

mad[0][0]:0

mad[0][1]:0

mad[0][1]:1

mad[0][1]:1

mad[0][1]:1

mad[0][1]:1

mad[0][1]:1

mad[0][1]:0

mad[0][1]:0

Output Table Format

0 0 1

1 1 1

1 0 0

(Sum is not displayed because it is an odd value)

Answer 1

using namespace std;


#define ROW	3
#define COL	3


void InitialsMatrix(int r, int c) 
{
	int MadMatrix[r][c],t,Sum=0;
	for(int i=0;i<r;i++)
	{
		for(int j=0;j<c;j++)
		{
			t=2;
			while(t<0 ||t>1)
			{
				cout<<"\n\tmad["<<i<<"]["<<j<<"] = "; cin>>t;
				MadMatrix[i][j]=t;
			}
			Sum=Sum+t;
		}
	}
	cout<<"\n\tInput Matrix: "<<"\n";
	for(int i=0;i<r;i++)
	{
		for(int j=0;j<c;j++)
		{
			cout<<"\t"<<MadMatrix[i][j];
		}
		cout<<"\n";
	}
	if(Sum%2==0)	cout<<"\n\n\tSum of Matrix Elements = "<<Sum;
	else			cout<<"\n\n\tSum is not displayed because it is an odd value.";
}


int main()
{
	InitialsMatrix(ROW,COL);
}