Answer to Question #271298 in C++ for Immanuel

Question

Sample Run 1:

Enter 10 integers: 1 2 3 4 5 6 7 8 9 10

2 4 6 8 10

1 3 5 7 9

Sample Run 2:

Enter 10 grades: 78 79 80 81 82 83 67 66 65 90

The highest is 90.

The average is 77.10!

Sample Run 3:

Enter 10 integers: 1 2 3 4 5 6 7 8 9 10

Sum of even: 30

Sum of odd: 25

C++ code and sample runs

Answer 1

Sample run 1 source code

#include <iostream>


using namespace std;


int main()
{
    int arr[10];
    cout<<"\nEnter 10 integers: ";
    for(int i=0;i<10;i++){
        cin>>arr[i];
    }
    //print even numbers
    for(int i=0;i<10;i++){
        if(arr[i]%2==0)
            cout<<arr[i]<<" ";
    }
    cout<<endl;
    //print odd numbers
    for(int i=0;i<10;i++){
        if(arr[i]%2!=0)
            cout<<arr[i]<<" ";
    }


    return 0;
}

Sample run 2 source code

#include <iostream>


using namespace std;


int main()
{
    int grades[10];
    cout<<"\nEnter 10 grades: ";
    for(int i=0;i<10;i++){
        cin>>grades[i];
    }
    int highest=grades[0];
    int sum=0;
    for(int i=0;i<10;i++){
        if(grades[i]>highest)
            highest=grades[i];
        sum+=grades[i];
    }
    
    cout<<"\nThe highest is "<<highest<<".";
    cout<<"\nThe average is "<<(sum/10.0)<<"!";
    return 0;
}

Sample run 3 source code

#include <iostream>




using namespace std;




int main()
{
    int arr[10];
    cout<<"\nEnter 10 integers: ";
    int sumEven=0;
    int sumOdd=0;
    for(int i=0;i<10;i++){
        cin>>arr[i];
    }
    for(int i=0;i<10;i++){
        if(arr[i]%2==0)
            sumEven+=arr[i];
        else
            sumOdd+=arr[i];
    }
    
    cout<<"\nSum of even: "<<sumEven;
    cout<<"\nSum of odd: "<<sumOdd;




    return 0;
}