Answer to Question #259630 in C++ for jye

Question

Write a function that saves even numbers of an innuation array foreground to another with sufficiently distributed array space. Write the main program using that function in 2 cases:

The input array is the static array with the given elements

The input array is a dynamic array with the number of elements and elements imported from the keyboard

Displays the resulting array to the screen

Answer 1

#include <iostream>
using namespace std;

int GetEvenNumber(int numbers[], int size, int evenNumbers[]) {
    int n=0;
    for (int i=0; i<size; i++) {
        if (numbers[i] % 2 == 0) {
            evenNumbers[n] = numbers[i];
            n++;
        }
    }
    return n;
}


void PrintArray(int array[], int size) {
    for (int i=0; i<size; i++) {
        cout << array[i];
        if (i != size-1) {
            cout << ",  ";
        }
    }
    cout << endl;
}


int main() {
    const int N = 5;
    int a1[N] = {1, 2, 3, 4, 5};
    int even[N];
    int n;

    cout << "Static array: " ;
    PrintArray(a1, N);
    n = GetEvenNumber(a1, N, even);
    cout << "Even numbers: ";
    PrintArray(even, n);
    cout << endl;

    int size;
    cout << "Enetr size of the new array: ";
    cin >> size;

    int* a2 = new int[size];
    int* even2 = new int[size];

    cout << "Enter " << size << " numbers:" << endl;
    for (int i=0; i<size; i++) {
        cout << (i+1) << "-th number: ";
        cin >> a2[i];
    }
    cout << endl << "Dynamic array: ";
    PrintArray(a2, size);
    n = GetEvenNumber(a2, size, even2);
    cout << "Even numbers: ";
    PrintArray(even2, n);

    delete [] a2;
    delete [] even2;

    return 0;
}