Answer to Question #197722 in C++ for adil ramzan

Question

use for/while loop only to implement a calculator using ++ (increment) and -- (decrement) operators only. The operations that your calculator shall perform are limited, i.e. addition, subtraction, multiplication, division, remainder and absolute. Your program shall ask the user about the two input values and an operator, and then use the switch-case structure to run the required operation (addition, subtraction, multiplication, division or absolute (symbol ~)). Your program shall run correctly for positive input values only. Prototype are:  int addition(int n1,int n2);  int subtraction(int n1,int n2);  int multiplication(int n1,int n2);  int division(int num,int denom);  int remainder(int num,int denom);  int absolute(int num);Take only one input for absolute function.All functions inputs can be positive or negative except remainder function, whichaccept only positive values (>0).Take input and display output in main function.write a program for this problem

Answer 1

#include <iostream>
using namespace std;


int main()
{
    int one, two, result = 0, choice; // declaring variables
    cout << "First Input: "; // taking user input of two numbers
    cin >> one;
    cout << "Second Input: ";
    cin >> two;
    cout << "Operation: "; // taking user input of operation
    string op;
    cin >> op;
    if (op.compare("Addition") == 0)
        choice = 1;
    if (op.compare("Subtraction") == 0)
        choice = 2;
    if (op.compare("Multiplication") == 0)
        choice = 3;
    if (op.compare("Division") == 0)
        choice = 4;
  switch(choice)
  {
      case 1: // addition case
              for(int x=1; x<=two; x++)
                one++;
              result = one;
              break;
      case 2: // subtraction case
              for(int x=1; x<=two; x++)
                one--;
              result = one;
              break;
      case 3: // multiplication case
              for(int x=1; x<=two; x++)
                for(int y=1; y<=one; y++)
                result++;
              break;
      case 4: // division case
              int help = 0;
              for(;help < one;)
                {
                    for(int j=0; j<two; j++)
                    help++;
                    if(help <= one)
                        result++;
                }
                break;
    }
    cout << "Answer: " << result;
}