Create a program that will output the multiples of 5. It must start at 0 and show however many numbers the users asks for. In addition, the numbers should output on a new line every time a multiple of 100 is reached.
Prompt:
This program will output the multiples of 5. How many numbers do you want to see? [user types: 42]
Output:
0 5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 85 90 95 100
105 110 115 120 125 130 135 140 145 150 155 160 165 170 175 180 185 190 195 200
205
Notes and Hints:
1) You can use any type of loop, but there is an obvious choice here.
#include<iostream>
using namespace std;
int main(){
int n,i,sum=0;
cout<<"Please enter the total available number"<<endl;
cin>>n;
int scan[n];
for(i=0;i<n;i++){
cin>>scan[i];
}
for(int j=0;j<n;j++){
sum=5*scan[j];
printf("%d,",sum);
}
printf("\n");
for(int k=0;k<n;k++){
printf("%d,",(100+5*scan[k]));
}
return 0;
}
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