Answer to Question #166625 in C++ for Earl Davis Jr.

Question

We have talked a bit about how chars are really just ASCII integers. Let's see this in action. We will show the characters starting at ASCII 33 and end with a user-supplied number. Use a for loop to output the characters with two spaces between each.

 

Prompt:

This program will output the ASCII characters starting at 33

Enter the integer for the last ASCII character you wish to see:  [user types: 43]

 

Output:

! " # $ % & ' ( ) * +  

 

Notes and Hints:

1) You MUST use a FOR LOOP

2) Hint: Which operator from Chp 3 allows us to convert from one data type to another?

3) FYI only: http://www.asciitable.com/

Answer 1

//Solution-1

using namespace std;


main(void)
{
	int StartChar = 33,EndChar,n;
	cout<<"\nEnter the last character ASCII (decimal): "; cin>>EndChar;
	
	cout<<"\n\nCharacters from ASCII = "<<StartChar<<" to ASCII = "<<EndChar<<endl;
	for(n=int(StartChar);n<=int(EndChar);n++)
	{
		cout<<char(n)<<" ";
	}
	return(0);
}

Solution-2

cout<<char(n)<<" ";
The above statement converts ASCII code to character and displays the equivalent character.

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