Answer to Question #156468 in C++ for Ansil Rahim

Question

Define a class Person with members name,age,gender and location type. Define another 

class which is derived from Person named Salary with members basic,da and hra .Calculate 

net salary of a person . HRA depends on the location type. Location type can be 'A','B',or 'C'. 

For 'A' hra is 500, for 'B' hra is 1000, and for 'C' it is 1500.

Answer 1

#include <iostream>
using namespace std;

// Person class
class Person
{
    char name[30];
    int age;
    char gender[6];
    char locationType[10];
   public:
   void getDetails()
    {
       cout<<"\n\n ------Please enter person details---";
       cout<<"\n Person Name:";
       cin>>name;
       cout<<"\n Person age(in digit):";
       cin>>age;
       cout<<"\n Gender:";
       cin>>gender;
       cout<<"\n Location Type:";
       cin>>locationType;
    }
    void displayDetails()
    {
    cout <<"\n Person Name:"<<name;
    cout <<"\n Person age:"<<age;
    cout <<"\n Gender:"<<gender;
    cout <<"\n Location Type:"<<locationType;
    }
   };
 
   class Salary: public Person
   {
       float basic, da, hra, netPayout;
       public:
       void getPayDetails()
       {
         getDetails();
         
        cout << "Enter the Basic pay:";
        cin>>basic;
        cout << "Enter the Humen Resource Allowance:";
        cin>>hra;
        cout << "Enter the Dearness Allowance :";
        cin>>da;
        
       }
       void calculate()
       {
        netPayout = basic + hra + da;
         }
         
    void display() {
        displayDetails();
        cout <<"\nEmployee Basic pay:"<<basic;
        cout <<"\nEmployee Humen Resource Allowance:"<<hra;
        cout <<"\nEmployee Dearness Allowance:"<<da;
        cout <<"\nEmployee Net Pay:"<<netPayout<<endl;
    }
   };

int main() {

    int i, n;
    char ch;
    Salary s[10];
    
    cout << "Number of available person:";
    cin>>n;
    for (i = 0; i < n; i++) {
        cout << "\nPerson Details # "<<(i+1)<<" : ";
        s[i].getPayDetails();
        s[i].calculate();
    }

    for (i = 0; i < n; i++) {
        s[i].display();
    }
    
    
    return 0;
}