In the Byteland country a string "S" is said to super ascii string if and only if count of each
character in the string is equal to its ascii value.
In the Byteland country ascii code of 'a' is 1, 'b' is 2 ...'z' is 26.
Your task is to find out whether the given string is a super ascii string or not.
Input Format:
First line contains number of test cases T, followed by T lines, each containing a string "S".
Output Format:
For each test case print "Yes" if the String "S" is super ascii, else print "No"
Constraints:
1<=T<=100
1<=|S|<=400, S will contains only lower case alphabets ('a'-'z').
Sample Input and Output
SNo. Input Output
2
1
bba
scca
Explanation:
In case 1, viz. String "bba" -
The count of character 'b' is 2. Ascii value of 'b' is also 2.
The count of character 'a' is 1. Ascii value of 'a' is also 1.
Hence string "bba" is super ascii.
1
Expert's answer
2015-08-04T02:18:48-0400
In the Byteland country a string "S" is said to super ascii string if and only if count of each character in the string is equal to its ascii value. In the Byteland country ascii code of 'a' is 1, 'b' is 2 ...'z' is 26. Your task is to find out whether the given string is a super ascii string or not. Input Format: First line contains number of test cases T, followed by T lines, each containing a string "S". Output Format: For each test case print "Yes" if the String "S" is super ascii, else print "No" Constraints: 1<=T<=100 1<=|S|<=400, S will contains only lower case alphabets ('a'-'z'). Sample Input and Output SNo. Input Output 2 1 bba scca Explanation: In case 1, viz. String "bba" - The count of character 'b' is 2. Ascii value of 'b' is also 2. The count of character 'a' is 1. Ascii value of 'a' is also 1. Hence string "bba" is super ascii.
Solve #include <stdio.h>
int main() { char str[400]; //for input line int res[100]={0}; //result of check int T; printf("Input number of string: "); scanf("%d",&T); int j; for(j=0;j<T;j++) { printf("Input string # %d: ",j+1); scanf("%s",str);
int i=0; //calculate number of symbols: int numbers[26]={0}; while(str[i]!='\0') { if((str[i]>='a')&&(str[i]<='z')) numbers[str[i]-'a']++; i++; } //check numbers and number in super ascii: int isAscii=1; for(i=0;i<26;i++) if((numbers[i]>0)&& (numbers[i]!=(i+1))) { isAscii=0; break; } if(isAscii==1) res[j]=1; }
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