Question

main( )
{
int x = 10, y = 20 ;
if ( x == y ) ;
printf ( "\n%d %d", x, y ) ;

Answer 1

Solution
You are declaring the x and y variables with values 10 for x and 20 for y. In next line you have small “trap”. You can see condition that if variable x equal variable y something must happen, but it will not work, because after closing bracket you see semicolon. Later you have function which will print x and y variables. In result the line of code “if ( x == y ) ;” is pointless.
If you will have code like this:
main( )
{
int x = 10, y = 20 ;
if ( x == y ) printf ( "\n%d %d", x, y );
In output you will see nothing, because condition “if ( x == y )” will work and variable x doesn't equal variable y, so those variables will not print.
Answer
In output you will see: 10 20.