Question

int a=6,b=3;

printf("%d",(++a*b--));

Answer 1

++a -- increments value of a and returns it's new value

printf("%d", ++a); //7

b-- -- decrements value of b and returns it's old value

printf("%d", b--); //3

So, the value of (++a*b--) equals (a+1)*b = 21

So the result of this line of code

printf("%d", (++a*b--));

would be 21