Consider an object projected straight upward from z=0 with an initial speed of u. Assume that the object is subjected to a linear drag force of the form D=-mKv
a)From the first principle show that t=1/K In(g+Ku/g+Kv) and use this result to find the time taken to reach the maximum height
b)Find the expression for the speed v as a function of time and find the limiting speed
Answer
a) for these type of D=-mKv and t=1/K In(g+Ku/g+Kv) case force is calculate by using by second law of newton
"F=ma\\\\\nm\\frac{dv}{dt}=ma"
b) putting at value of t=1/K In(g+Ku/g+Kv) we get expression for velocity of particle.
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