n a jump spike, Mark Angel slams the volleyball from a height of 2.3 m with a speed of 18 m/s at 24° below the horizontal. How far on the opposite side will the ball land?
Answer
d=18cos249.8(18sin24+((18sin24)2+2(9.8(2.3))=29md= \frac{ 18cos24}{9.8} (18sin24+\sqrt{ ( (18sin24) 2 +2(9.8(2.3) } ) =29 md=9.818cos24(18sin24+((18sin24)2+2(9.8(2.3))=29m
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