A nucleus has a radius of 4 Fermis. Use the uncertainty principle to estimate the kinetic energy for a neutron localized inside the nucleus. Do the same for an electron.
Answer
So uncertainty in kinetic energy
=ℏ2πR=6.626∗10−342∗3.14∗4∗10−15=1.06∗10−19J=\frac{\hbar}{2\pi R}\\=\frac{6.626*10^{-34}}{2*3.14*4*10^{-15}}\\=1.06*10^{-19}J=2πRℏ=2∗3.14∗4∗10−156.626∗10−34=1.06∗10−19J
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