h2d2ψ(x)2mdx2+V(x)ψ(x)=Eψ(x)\frac{h^2d^2\psi(x)}{2m{dx^2}}+V(x)\psi(x)= E\psi(x)2mdx2h2d2ψ(x)+V(x)ψ(x)=Eψ(x)
and
ψ(x)=Axe−x2c2\psi(x) = Ax{e^\frac{-x^2}{c^2}}ψ(x)=Axec2−x2 having E=0E = 0E=0
Therefore; h2d2ψ(x)2mdx2+V(x)ψ(x)=0\frac{h^2d^2\psi(x)}{2m{dx^2}}+V(x)\psi(x)= 02mdx2h2d2ψ(x)+V(x)ψ(x)=0
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